15. Two metal plates are connected to a battery and a current meter. When a light beam with tunable energy E is shined on one of the plates, the values read by the current meter is plotted as a function of E. E0 corresponds to the photon density of 1012cm-3and the photon wavelength of 200 nm. When the incident photon wavelength is increased to 400 nm, what is the photon density to obtain the current value of 5 μA?
(A)2✖1012 cm-3
(B)4✖1012 cm-3
(C)8✖1022cm-3
(D)1012-3
(E)None of the above
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統計: 尚無統計資料
統計: 尚無統計資料
詳解 (共 1 筆)
#7446822
所以首先第一步要先了解電磁波的能量密度和電場振幅的關係

然後波長增加,單顆光子能量會減少

然後計算光子密度

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所以也可以記結合後的式子
光子能量密度會正比於電場振幅的平方再乘上波長
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