I. (50%) 1.1. (10%) Let X have a distribution with p.d.f.
$f(x) = \frac{e^{-x}}{(1+e^{-x})^2}, \quad -\infty < x < \infty.$
What is the distribution of $Y = 1/(1+e^{-X})$?
I. (50%) 1.1. (10%) Let X have a distribution with p.d.f.
$f(x) = \frac{e^{-x}}{(1+e^{-x})^2}, \quad -\infty < x < \infty.$
What is the distribution of $Y = 1/(1+e^{-X})$?