I. (50%)
1.1.(10%) Let X have a distribution with p.d.f.
$$f(x) = \frac{e^{-x}}{(1+e^{-x})^2}, -\infty < x < \infty.$$
What is the distribution of $Y = 1/(1+e^{-X})$?
阿摩線上測驗
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阿摩線上測驗
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I. (50%)
1.1.(10%) Let X have a distribution with p.d.f.
$$f(x) = \frac{e^{-x}}{(1+e^{-x})^2}, -\infty < x < \infty.$$
What is the distribution of $Y = 1/(1+e^{-X})$?